A baseball is thrown vertically upward at a rate of 65 feet per second from an initial height of 4 feet. Use the projectile formula h = − 16 t 2 + v 0 t + h 0 to determine when the height of the ball will be 93 feet.
Accepted Solution
A:
Answer:At time t = 2.03 s height of ball = 93 feetStep-by-step explanation:We have h(t) = − 16 t² + v₀ t + h₀A baseball is thrown vertically upward at a rate of 65 feet per second from an initial height of 4 feet. Initial speed, v₀ = 65 ft/sInitial height, h₀ = 4 ftSubstituting h(t) = − 16 t² + 65 t + 4Now we need to find time when h(t) = 93 ft 93 = − 16 t² + 65 t + 4 16 t² - 65 t + 89 = 0 t = 2.03 s or t = 2.03 sAt time t = 2.03 s height of ball = 93 feet