Q:

Dwayne is selling hamburgers and cheeseburgers. He has 100 burger buns. Each hamburger sells for $3, and each cheeseburger sells for $3.50. Which system of inequalities represents the number of hamburgers, h, and the number of cheeseburgers, c, he must sell to have sales of at least $80?

Accepted Solution

A:
Answer:[tex]h + c \leq 100;\, 3h + 3.5c \geq 80[/tex]Step-by-step explanation:In this question, we know that:Dawyne as 100 burger bunsHamburgers sell for $3 eachCheeseburger sells for $3.50He at least need $80 in salesWith the information above, we can make our inequalities.The letter "h" would be representing hamburgers in this case. Since each hamburger cost $3, we would put it as 3h.The letter "c" would be representing cheeseburgers. Since each cheeseburger cost $3.50, we would put it as 3.5c.He needs to at least $80, meaning that he needs to make $80 or more.So when we put those together, the inequality should be:[tex]3h + 3.5c \geq 80[/tex]We're not done yet, we also have another inequality to make.We know that he has 100 hamburger buns, but we don't know how many hamburgers or cheeseburgers he sold. We would represent is as "less than or equal to" because we can't get any higher than 100.So this would be represented as:[tex]h + c \leq 100[/tex]I hope this helped you out.Good luck on your academics.Have a fantastic day!